1st Law for isochoric, isothermal and adiabatic process. • Temperature Three special ideal gas processes: one of, W or Q is 0. • fix volume by 0 for isobaric. Explain the differences among the simple thermodynamic processes—isobaric, isochoric, isothermal, and adiabatic. Calculate total work done in a cyclical. If I remember my thermodynamics correctly, all reversible processes must be quasistatic but the opposite is not the case. For a process to be.

Author: Tajora Magor
Country: Netherlands
Language: English (Spanish)
Genre: Personal Growth
Published (Last): 6 April 2013
Pages: 434
PDF File Size: 3.59 Mb
ePub File Size: 12.27 Mb
ISBN: 528-5-93578-673-2
Downloads: 75819
Price: Free* [*Free Regsitration Required]
Uploader: Sajin

The above prolem should be fixed now. I have been working on project related to open source. Notify me of new comments via email.

Are all quasi-static processes reversible? Click to toggle author information expand message area. These are just the four that are kind of the simplest to deal with mathematically. And we know force times the distance by which you apply that force is just the work. ispbaric

Processss other words, the system is dynamically connected, by a movable boundary, to a constant-pressure reservoir. So it would be height times the area of the piston. Let’s try to figure out what the area under isothedmal curve represents.

Which of these is changing in this process? So you have to be careful. And then there’s a certain height. You can do something like this. It could be anywhere on this PV Diagram, any horizontal line is gonna be an isobar, an isobaric process. Could you help me know how I can download this applet?

All I know is, my volume better be increasing, so this is increasing volume, that’s increasing volume, that’s increasing volume. I’ll explain the next three thermodynamic processes in the next video. PV diagrams – part 1: Piston going down means decreasing volume.


PV diagrams – part 1: Work and isobaric processes (video) | Khan Academy

isochorci A place to start would be the Wikipedia article on quasistatic processes, whilst this https: And what I get is F times A over A times the change in the height. That sounds very complicated. The size of the width, no negatives. So this area isotjermal the work, this area, the value of this area equals the amount of work done on the gas or by the gas. Piston can move up or down, changing the amount of volume, right? There’s infinitely many ways it can take.

If you calculate this P adiabtic V and you go to your first law equation, which remember, says delta U is Q plus W, well you can’t just plug in the value of P delta V. Dear Proffesor, I use your applets for some experiments qith students in high school.

But we do know if you have an isobaric process, if it really is an isobaric process, then we can rewrite the first law. That is to say the volume was decreasing.

So there’s a certain pressure down from the outside and then there’s the weight of the piston divided by the area gives another pressure. We may say that the system is dynamically insulated, by a rigid boundary, from the environment. If there’s any gas inside, it can’t be zero. Home Questions Tags Users Unanswered. Makes it me easier for me to understand.


Thermal dynamic processes: isobaric, isochoric, isothermal, adiabatic processes

So this formula won’t work for the whole process. Implications for the first law. It is fixed now.

Well, if you wanna maintain constant pressure, you can’t go up or down, because if I were to go up, my pressure would be increasing. Pressure’s gotta go up, so maybe it does something like that.

PV diagrams – part 1: Work and isobaric processes

It’s not so bad, just allow the piston to come into equilibrium with whatever atmospheric pressure plus the weight of this piston is. From my understanding so far, I think that a quasi-static process is one where the system is in thermal equilibrium with itself as well as the surroundings and the process takes place infinitesimally slow.

So that movable piston can change that amount of volume. So even though it might be difficult to find this area, it’s always true that if I could find this xdiabatic under any process, this area does represent the work done.

By clicking “Post Your Answer”, you acknowledge that you have read our updated terms of serviceprivacy policy and cookie policyand that your continued use of the website is subject to these policies.

And if my piston goes down, I better be going to the left on this graph somehow. Times the distance by which this height changes.